WebFeb 28, 2024 · Below please see the exact commands and Stata responses: destring NUM_CUENTA, replace NUM_CUENTA: all characters numeric; replaced as double . destring TITULAR, replace TITULAR: contains nonnumeric characters; no replace . destring CREDITO_2024_01, replace CREDITO_2024_01: all characters numeric; replaced as double WebApr 12, 2024 · Method 2: Find and Replace Strings (Case-Sensitive) Sub FindReplace () Range ("A1:B10").Replace What:="Mavs", Replacement:="Mavericks", MatchCase:=True …
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WebSome basic examples of replacing variables: Replace all values of variable STATE with the string Utah replace STATE = "Utah" Replace values of variable STATE with the string Utah only in the first 10 cases in your dataset replace STATE = "Utah" in 1/10 WebSep 17, 2016 · Once you've established femedc as a numeric variable, you cannot replace its value with those of a string variable. So, of course, because hv106_05 is, you say, a string, Code: replace femedc = hv106_05 if hv101_05 == "Co-spouse" hv101_05 == "Wife or husband" hv101_05 == "co-spous" hv101_05 == "wife or" chickens that lay biggest eggs
Introduction to Stata: Creating and Changing Variables
WebJan 18, 2024 · Click Replace or Replace All, to replace the line breaks with space characters. Find and Replace Troubleshooting Tip #1. If you try to find line breaks a second time, Excel might say it can't find any. ... delimiter - A text string to separate the joined text items. Our formula will use a line break: CHAR(10) ignore_empty - ignore blank cells ... WebJul 16, 2024 · Extract the desired part of a string (using two different methods) replace var = substr (var,-5,5) “20/02/2024 12:35” “12:35” Extract the last 5 characters from a string replace var = strtoname (var) ” 1v 123″ “_1v_123” Convert a string to a format that can be later used as variable name replace var = strtrim (var) replace var = strltrim (var) WebNote that this problem can only arise for string variables, so you need to work on those only. Taking you at your word that spaces always mean missing, then ds, has (type string) qui foreach v in `r (varlist)' { replace `v' = "" if trim (`v') == "" } -- or almost equivalently use replace `v' = trim (`v') Share Improve this answer Follow chickens that lay black eggs for sale